55x^2+1280x+6400=0

Solution for 55x^2+1280x+6400=0 equation:

55x^2+1280x+6400=0

a = 55; b = 1280; c = +6400;
Δ = b2-4ac
Δ = 12802-4·55·6400
Δ = 230400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{230400}=480$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1280)-480}{2*55}=\frac{-1760}{110}
=-16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1280)+480}{2*55}=\frac{-800}{110}
=-7+3/11
$